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Example:''' Solving the quadratic equation.
Suppose {$ %height=70px% ax^2+bx+c=0 text( with ) a!=0 $}
We first divide by a to get {$ %num=1% x^2+b/ax+c/a=0 $}
Then we complete the square and obtain {$ %num% x^2+b/ax+(b/(2a))^2-(b/(2a))^2+c/a=0 $}
The first three terms factor to give {$ %num% (x+b/(2a))^2=(b^2)/(4a^2)-c/a $}
Now we take square roots on both sides and get {$ %num% x+b/(2a)=+-sqrt((b^2)/(4a^2)-c/a) $}
Finally we move {$ b/(2a) $} to the right and simplify to get the two solutions: {$ %num=5% x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a) $}
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